| /* |
| * Copyright 2010 Tilera Corporation. All Rights Reserved. |
| * |
| * This program is free software; you can redistribute it and/or |
| * modify it under the terms of the GNU General Public License |
| * as published by the Free Software Foundation, version 2. |
| * |
| * This program is distributed in the hope that it will be useful, but |
| * WITHOUT ANY WARRANTY; without even the implied warranty of |
| * MERCHANTABILITY OR FITNESS FOR A PARTICULAR PURPOSE, GOOD TITLE or |
| * NON INFRINGEMENT. See the GNU General Public License for |
| * more details. |
| */ |
| |
| #include <linux/types.h> |
| #include <linux/string.h> |
| #include <linux/module.h> |
| #include <arch/chip.h> |
| |
| void *memset(void *s, int c, size_t n) |
| { |
| uint32_t *out32; |
| int n32; |
| uint32_t v16, v32; |
| uint8_t *out8 = s; |
| int to_align32; |
| |
| /* Experimentation shows that a trivial tight loop is a win up until |
| * around a size of 20, where writing a word at a time starts to win. |
| */ |
| #define BYTE_CUTOFF 20 |
| |
| #if BYTE_CUTOFF < 3 |
| /* This must be at least at least this big, or some code later |
| * on doesn't work. |
| */ |
| #error "BYTE_CUTOFF is too small" |
| #endif |
| |
| if (n < BYTE_CUTOFF) { |
| /* Strangely, this turns out to be the tightest way to |
| * write this loop. |
| */ |
| if (n != 0) { |
| do { |
| /* Strangely, combining these into one line |
| * performs worse. |
| */ |
| *out8 = c; |
| out8++; |
| } while (--n != 0); |
| } |
| |
| return s; |
| } |
| |
| /* Align 'out8'. We know n >= 3 so this won't write past the end. */ |
| while (((uintptr_t) out8 & 3) != 0) { |
| *out8++ = c; |
| --n; |
| } |
| |
| /* Align 'n'. */ |
| while (n & 3) |
| out8[--n] = c; |
| |
| out32 = (uint32_t *) out8; |
| n32 = n >> 2; |
| |
| /* Tile input byte out to 32 bits. */ |
| v16 = __insn_intlb(c, c); |
| v32 = __insn_intlh(v16, v16); |
| |
| /* This must be at least 8 or the following loop doesn't work. */ |
| #define CACHE_LINE_SIZE_IN_WORDS (CHIP_L2_LINE_SIZE() / 4) |
| |
| /* Determine how many words we need to emit before the 'out32' |
| * pointer becomes aligned modulo the cache line size. |
| */ |
| to_align32 = |
| (-((uintptr_t)out32 >> 2)) & (CACHE_LINE_SIZE_IN_WORDS - 1); |
| |
| /* Only bother aligning and using wh64 if there is at least |
| * one full cache line to process. This check also prevents |
| * overrunning the end of the buffer with alignment words. |
| */ |
| if (to_align32 <= n32 - CACHE_LINE_SIZE_IN_WORDS) { |
| int lines_left; |
| |
| /* Align out32 mod the cache line size so we can use wh64. */ |
| n32 -= to_align32; |
| for (; to_align32 != 0; to_align32--) { |
| *out32 = v32; |
| out32++; |
| } |
| |
| /* Use unsigned divide to turn this into a right shift. */ |
| lines_left = (unsigned)n32 / CACHE_LINE_SIZE_IN_WORDS; |
| |
| do { |
| /* Only wh64 a few lines at a time, so we don't |
| * exceed the maximum number of victim lines. |
| */ |
| int x = ((lines_left < CHIP_MAX_OUTSTANDING_VICTIMS()) |
| ? lines_left |
| : CHIP_MAX_OUTSTANDING_VICTIMS()); |
| uint32_t *wh = out32; |
| int i = x; |
| int j; |
| |
| lines_left -= x; |
| |
| do { |
| __insn_wh64(wh); |
| wh += CACHE_LINE_SIZE_IN_WORDS; |
| } while (--i); |
| |
| for (j = x * (CACHE_LINE_SIZE_IN_WORDS / 4); |
| j != 0; j--) { |
| *out32++ = v32; |
| *out32++ = v32; |
| *out32++ = v32; |
| *out32++ = v32; |
| } |
| } while (lines_left != 0); |
| |
| /* We processed all full lines above, so only this many |
| * words remain to be processed. |
| */ |
| n32 &= CACHE_LINE_SIZE_IN_WORDS - 1; |
| } |
| |
| /* Now handle any leftover values. */ |
| if (n32 != 0) { |
| do { |
| *out32 = v32; |
| out32++; |
| } while (--n32 != 0); |
| } |
| |
| return s; |
| } |
| EXPORT_SYMBOL(memset); |